Question 24… please someone help thank you!

72 in^2

Step-by-step explanation:

The area of the square in the middle is

A = s^2 = 6^2 = 36

The area of the triangle on the left is

A =1/2 bh = 1/2 ( 6*6) = 18

The area of the triangle on the right

A = 1/2 bh = 1/2(6*6) = 18

Add the areas together

36+18+18 = 72

Area of the middle square = 6 x 6 = 36

Area of a triangle is 1/2 x base x height:

Area = 1/2 x 6 x 6 = 18

Both triangles have a base of 6 and height of 6 so both triangles have the same area.

Total area = 36 + 18 + 18 = 72 square in.

The answer is D. 72

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option

0 is its x and y coordinate