3y^4/3y^2-6=10 please help I will. mark it as the brainliest answer!​

y=4

Step-by-step explanation:

you multiply through by 3y^2

3y^4 - 18y^2 =30y^2

Collect like terms

3y^4=48y^2

divide through by y^2

3y^2=48

divide through by 3

y^2=16

take the square root of both sides

y=4

let's call the solutions x₁ = (5 - 2√7)/3 and x₂ = (5 + 2√7)/3

then the equation is (x-x₁)(x-x₂) = 0

if you fill that in you get a lot of numbers which you can recognize as ax²+bx+c=0.

step-by-step explanation:

you can see that a=1 (there is just an x²)

b = (-5 -2√7 + 2√7 - 5)/3 = -10/3

c = -2√7)/3 ) * (-5+2√7)/3) = -1/3

so your answer is 3x^2 – 10x – 1 = 0