What is the equation of the line that is perpendicular to the line y = 2x + 5 and passes through the point (-4, 2)?

y = -1/2x

Step-by-step explanation:

If two lines are perpendicular to each other, they have opposite slopes.

The first line is y = 2x + 5. Its slope is 2. A line perpendicular to this one will have a slope of -1/2.

Plug this value (-1/2) into your standard point-slope equation of y = mx + b.

y = -1/2x + b

To find b, we want to plug in a value that we know is on this line: in this case, it is (-4, 2). Plug in the x and y values into the x and y of the standard equation.

2 = -1/2(-4) + b

To find b, multiply the slope and the input of x (-4)

2 = 2 + b

Now, subtract 2 from both sides to isolate b.

0 = b

Plug this into your standard equation.

y = -1/2x + 0 or y = -1/2x

This equation is perpendicular to your given equation (y = 2x + 5) and contains point (-4, 2)

Hope this helps!

step-by-step explanation:

this is not possible to solve with the info given.   you need at least an one angle somewhere.

step-by-step explanation: