Two sailboats leave a harbor in the Bahamas at the same time. The first sails at 25 mph in a direction 340°. The second sails at 29 mph in a direction 210°. Assuming that both boats maintain speed and heading, after 5 hours, how far apart are the boats? A. 157.4 mi
B. 212 mi
C. 175 mi
D. 244.8 mi

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  D. 244.8 mi

Step-by-step explanation:

The law of cosines can be used to find the distance between the boats.

The first boat will have traveled (5 h)×(25 mi/h) = 125 mi. The second boat will have traveled (5 h)×(29 mi/h) = 145 mi. The angle between their travel directions is 340° -210° = 130°.

  c² = a² +b² -2ab·cos(C) . . . . . for a=125, b=145, C=130°

  c² ≈ 59951.05

  c ≈ √59951.05 ≈ 244.8 . . . miles

The boats are about 244.8 miles apart after 5 hours.

hello :

by applying the distributive property :

6 × 4.3 = 6 × ( 4 + 0.3 )

            =   (6 ×   4) + (6 ×   0.3)

            = 24 + 1.8

6 × 4.3 = 25.8

you ignore the remainder, therefore the answer is y = x+2

step-by-step explanation:

you have to divide the denominator by the numerator. you can use synthetic division or long division.

[-5] .     1 .     7 .     11

x + 2 + 1/x+5