A plane flies 1.2 hours at 120 mph on a bearing of 20°. It then turns and flies 3.3 hours at the same
speed on a bearing of 110°. How far is the plane from
its starting point?

9514 1404 393

  421.4 miles

Step-by-step explanation:

The flight legs are orthogonal, so the distance can be found using the Pythagorean theorem:

  1.2 h × 120 mph = 144 mi

  3.3 h × 120 mph = 396 mi

The distance at the end of the second flight leg is ...

  d = √(144² +396²) = √177552 ≈ 421.37

The plane is about 421.4 miles from its starting point.

The heading to its end point is 20° +arctan(3.3/1.2) ≈ 90.02°.

step-by-step explanation:

this is not possible to solve with the info given.   you need at least an one angle somewhere.

1.true 2.false? ? i think. .

step-by-step explanation: