Solve the equation below through elimination. -3x-3y=3 -5x+2y=19

HOW TO SOLVE SYSTEMS OF EQUATIONS BY ELIMINATION

To solve systems of equations by elimination, we want to eliminate one of the variables. To do this, we want to cancel out a certain variable in both equations. For example, if you had 8x in one equation and -8 x in another, you could combine the two equations and the x would be gone!

THE SOLUTION

In our case, though, we don't have anything we can combine to cancel out the variables. But, what we can do is multiply the first equation by three. If we do this, now we have a 9x in the top and a -9x in the bottom. Then, we can solve for y!

SOLVING FOR Y

Multiply first equation by three

9x+6y=57

Combine top and bottom equations

14y=28

We divide both sides by 14.

y=2

SOLVING FOR X

Now, we can simply plug our y-value into one of the original equations and then solve for x.

3x+4=19

We subtract 28 from both sides.

3x=15

We divide both sides by 3.

x=5

Therefore, our solution is (5,2) or x=5 and y=2.

I hope that this helps! Have a wonderful day! :D

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!

a is the right answer