Help quick! I'll mark your answer as the brainliest if your answer is correct! Jin is asked to graph this system of equations:
3x + 4y = 3
4y + 3x = 4
How many times will the lines intersect?

A. The lines will not intersect, because this system has no solutions.
B. The lines will intersect infinitely many times, because they are identical.
C. There is no way to tell without graphing the lines first
D. The lines will intersect once, because this system has one solution.

They would never intersect because they are parallel lines. You can tell they are parallel lines because they have the same slope and they have a different y-intercept. However, this doesn't mean that there was no solutions, there were, thats how i was able to tell what their slopes and y-intercepts were. So if there is an answer that you can choose from that explains that they won't intersect because they are parallel then that is the correct answer. It may be C, but I would see if there is another option.

step-by-stp

the correct answer is the section c

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}