In order for the parallelogram to be a rectangle, x = [?].
Diagonal AC =7x - 35
Diagonal BD = 3x + 45

The graph of the quadratic function shown on the left is y = –0.7(x + 3)(x – 4). the roots, or zeros, of the function are . determine the solutions to the related equation 0 = –0.7(x + 3)(x – 4). the solutions to the equation are x =

Hello i need some with trigonometric substitutions. [tex]\int\limits^a_b {x} \, dx[/tex]

Find the arc length parameter along the given curve from the point where tequals=0 by evaluating the integral s(t)equals=integral from 0 to t startabsolutevalue bold v left parenthesis tau right parenthesis endabsolutevalue d tau∫0tv(τ) dτ. then find the length of the indicated portion of the curve r(t)equals=1010cosine tcost iplus+1010sine tsint jplus+88t k, where 0less than or equals≤tless than or equals≤startfraction pi over 3 endfraction π 3.