A psychology professor assigns letter grades on a test according to the following scheme. A: Top 14% of scores B: Scores below the top 14% and above the bottom 65% C: Scores below the top 35% and above the bottom 16% D: Scores below the top 84% and above the bottom 9% F: Bottom 9% of scores Scores on the test are normally distributed with a mean of 68.4 and a standard deviation of 9.7. Find the numerical limits for a B grade. Round your answers to the nearest whole number, if necessary.

The numerical limits for a B grade are 72 and 79, that is, a score between 72 and 79 results in a B grade.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean and standard deviation , the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Scores on the test are normally distributed with a mean of 68.4 and a standard deviation of 9.7.

This means that

Find the numerical limits for a B grade.

Below the 100 - 14 = 86th percentile and above the 65th percentile.

65th percentile:

X when Z has a p-value of 0.65, so X when Z = 0.385.

86th percentile:

X when Z has a p-value of 0.86, so X when Z = 1.08.

The numerical limits for a B grade are 72 and 79, that is, a score between 72 and 79 results in a B grade.

f(x) has value 150 at x= 0

and 0 at x= 3

so d(f(x))/dt = slope = -150/3 = -50