2) Find the sum of the first 50 terms of the following series, to the nearest integer.
6, 10, 14,...

The sum of the first 50 is 5200

Step-by-step explanation:The given sequence is a linear sequence.

So, first we calculate the common difference

d=t2-t1

d=10-6=4

The sum of the first 50 terms is then calculated using: sorry it wont let me copy and paste my explo and im lazy

5,200

Step-by-step explanation:

6, 10, 14, ...

Sum = [ number of terms(first term+last term) ] / 2

-we know there are 50 terms

-we now the first term is 6

-we need to find the last term

last term = first term + (n-1)* difference between first and second term

last term = 6 + (50-1) * (10-6)

last term = 6 + 49*4 = 202

Sum = [ number of terms(first term+last term) ] / 2

Sum = [ 50 ( 6 + 202) ] / 2 = 5,200

x=17

step-by-step explanation:

solve 3x-24=x+10

then that makes it 2x=34 because you subtract an x from both sides to get rid of the one on the right, and then you add 24 to both sides to get rid of the 24 on the left

divide by both sides by 2 to get your answer so that you can get your answer

78.59 is the mean

step-by-step explanation: