Mathematics, 14.07.2021 20:00 edwmal638
How would you explain the relationship between
the real zero(s) of the function and x-intercept(s)
of the graph?
Since the graph crosses the x-axis at x = -2,
the function has a real zero of x = -2.
O
Since the graph never crosses the x-axis, the
function has no real zeros.
O
Since the graph eventually crosses the x-
axis, the function has a real zero.
nce the graph crosses the y-axis at 9, the
1
function results in a real zero of x = 9 ?.
Answers: 2
Mathematics, 21.06.2019 13:00
In the diagram below, dab and dac are adjacent angles. if mdac = 25°, what is mdab in degrees? what is mbac in degrees?
Answers: 3
Mathematics, 21.06.2019 23:30
Determine if the following statement is true or false. the normal curve is symmetric about its​ mean, mu. choose the best answer below. a. the statement is false. the normal curve is not symmetric about its​ mean, because the mean is the balancing point of the graph of the distribution. the median is the point where​ 50% of the area under the distribution is to the left and​ 50% to the right.​ therefore, the normal curve could only be symmetric about its​ median, not about its mean. b. the statement is true. the normal curve is a symmetric distribution with one​ peak, which means the​ mean, median, and mode are all equal.​ therefore, the normal curve is symmetric about the​ mean, mu. c. the statement is false. the mean is the balancing point for the graph of a​ distribution, and​ therefore, it is impossible for any distribution to be symmetric about the mean. d. the statement is true. the mean is the balancing point for the graph of a​ distribution, and​ therefore, all distributions are symmetric about the mean.
Answers: 2
How would you explain the relationship between
the real zero(s) of the function and x-intercept(s)<...
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