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Solution given:

let 3^xbe a

4*a*3-a²=27

a²-12a+27=0

a²-9a-3a+27=0

a(a-9)-3(a-9)=0

(a-9)(a-3)=0

either

a=9

3^x=3²

:.x=2

or

a=3

3^x=3^1

x=1

x=2,1

handwriting ta naramro xa tei vayera sorry la susmithai

i = 2 / - 5

step-by-step explanation:

evaluation of ( 2 - 4 ) ( p + q ) when p = 2 and q = 5 i, by putting values of p and q,