A total of $5000 is invested: part at 9% and the remainder at 14%. How much is invested at each rate if the annual interest is $460?

9514 1404 393

Step-by-step explanation:

Let x represent the amount invested at 14%. Then 5000-x is the amount invested at 9%. The interest earned is ...

  (14%)x +(9%)(5000 -x) = 460

  0.05x +450 = 460 . . . . . . . . . . simplify

  0.05x = 10 . . . . . . . . . . . . . . subtract 450

  x = 200 . . . . . . . . . . . . . . divide by 0.05

  5000-x = 5000-200 = 4800

$200 was invested at 14%; $4800 was invested at 9%.

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions

if you was gonna solve for a, a is a   < -12