Se reparten los bombones de una caja entre tres peques. Al primero se le da la mitad más 2, al segundo la mitad del resto más 2 y al último la mitad de lo
que queda más 2. ¿Cuántos bombones había en la caja si quedan 1 bombón
y medio?

tube or goog would be a great resource to with that question

where are the choices?

answer: solve 5\cdot 2^x=2405⋅2  

x

=2405, dot, 2, start superscript, x, end superscript, equals, 240.

solution

to solve for xxx, we must first isolate the exponential part. to do this, divide both sides by 555 as shown below. we do not multiply the 555 and the 222 as this goes against the order of operations!

\begin{aligned} 5\cdot 2^x& =240 2^x& =48 \\ \end{aligned}  

5⋅2  

x

2  

x

​    

=240

=48

​

step-by-step explanation:

just keep asking questions until you have a better understanding.

step-by-step explanation: