There are four multiple-choice questions on an exam, each with four possible answers (a) Determine the number of possible answer sequences for the four questions.
(b) Only one of the sets can contain all four correct answers. If you are guessing, so that you are as likely to choose one sequence of answers as another, what is the probability of getting all four answers correct? (Use 5 decimal places.)

i think it is 18

step-by-step explanation:

тgє qυєѕтισи αѕкє∂: ιи тнє ѕєяιєѕ σя яєα¢тισиѕ тgαт σ¢¢υя ιи ρнσтσѕуитнєѕιѕ, ωнι¢н fσямѕ ωнєи ℓιgнт ѕтяιкєѕ α мσℓє¢υℓє σf ¢нℓσяσρнуℓℓ.

α. мσℓє¢υℓє σf ωαтєя

в.тнєє-¢αявσи ѕυgαя

¢. "єχ¢ιтє∂" єℓє¢тяσи

∂. иα∂ρн

му αиѕωєя: ιт ιѕ ¢. "єχ¢ιтє∂" єℓє¢тяσи

нσρє ι ¢συℓ∂ нєℓρ υ

same question do you know the answer

1. she sold more on day 2 because if you turn .85 into a fraction{85/100} and you give 7/9 and 85/100 the same denominator{180} you can see which one has the bigger numerator and that one will be the most sold.

2. yes it is in simplest form, because if you look at 38 and 53 's greatest common factor, you cant find one so you cant reduce it

3. no, this is not a prime factorization because the numbers are not all prime numbers, the correct prime factorization is:   2 x 5 x 2

4.   in 12 days he will run and play trumpet again

work 4 4: 123123123123

                123412341234     in 12 days he will play the trumpet and run on the same day

step-by-step explanation:

i am normally pretty good at math, im new to this site, but im 1 grade ahead in my math, i luv math try my answers out, see how they work