1. The diagram shows a triangle OAB and point M is a point on AB. Rajah menunjukkan segi tiga OAB dan titik M ialah satu titik pada AB. A 5 5a M 0 B ub Given OA= 5a , OB = 4b and 2 AM =3MB, find vector Diberi OA=5a, OB = 4b dan 2 AM =3MB, cari vektor (a) AB [4b – 5a (b) OM 12 2a +​

we have to find the value of the x°=<GHC

In the triangle BDH,

<D=31°

<B=47°

we know that,

Sum of three angle of a triangle is 180°

According to the question,

<D+<B+<BHD=180°

31°+47°+<BHD=180°

78°+<BHD=180°

<BHD=180°-78°

<BHD=102°

But,

<GHC and <BHD forms a straight line

so,

<GHC+<BHD=180°

102°+x=180°

x=180°-102°

x=78°

Therefore,

The value of x is 78°

they are simplified

step-by-step explanation: