Given the circle with equation x+ y =17 a). Determine if the points D(-4, -1) and E(1, 4) are on the circle. Show all work

b). Find the equation of the perpendicular bisector of the chord DE

c). Verify that the perpendicular bisector from part b) passes through the center of the circle

Step-by-step explanation:

x+y=17 is NOT the equation for any circle. You have omitted the exponents. The equation for the circle should be

x^2 + y^2 = 17.

Plug the coordinates of D into the equation.

(-4)² + (-1)² = 17, so D is on the circle.

Plug the coordinates of E into the equation.

1² + 4² = 17, so E is on the circle.

Slope of DE = (-1 - 4)/(-4 - 1) = 1

Slope of perpendicular to DE is -1.

Midpoint of DE:  ((-4+1)/2, (-1+4)/2) = (-1.5, 1.5)

Point-slope equation for perpendicular bisector:

y-1.5 = -(x+1.5)

y = -x

Center of circle is (0,0)

0 = -0, so y=-x passes through the center.

$450.00 for 6 weeks

or

$300

step-by-step explanation:

$200.00 for first week $50.00 x5 equals $250 plus $200 equals $450.00 for six weeks.

$200 for first week

$200 x 0.10 = $20

$20 x 5 = $100

$200 + $100 = $300

answer: it is 8

step-by-step explanation:

you know why its 8