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The value of x is 40°

Solution given:

In triangle BCE

<C+<B+<E=180°[sum of interior angle of a triangle]

<C+60°+x°=180°

<C=180°-60°-x°

<C=120°-x°

again

<A=<C[exterior angle of a cyclic quadrilateral is equal to the opposite interior angle]

2x=120-x

2x+x=120°

3x°=120°

x°=120°/3°

x°=40°

Now we have to,

find the required value of x.

Then in ∆ BCE,

By sum of interior angle of a triangle.

→ <C+<B+<E = 180°

→ <C+60°+x = 180°

→ <C = 180-60-x

→ <C = 120-x

Now by the exterior angle of,

A cyclic quadrilateral is equal to the opposite interior angle.

→ <A = <C

→ 2x = 120-x

→ 2x+x = 120

→ 3x = 120

→ x = 120/3

→ x = 40°

Hence, 40° is the value of x.

ur right ive taken the test

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