2. Caveman Sampson chases a saber tooth tiger at an average speed of 3 miles per hour. The tiger runs at an average speed of 5 miles per hour, but rests for 2 hours after running for 2 hours. How long, in hours, will it take Sampson to catch the tiger if the tiger starts 2 miles in front of him and they start running at the same time? A. 7 hours B. 6 hours C. 5 hours D. 4 hours​

9514 1404 393

  D.  4 hours

Step-by-step explanation:

The tiger will run (5 mi/h)(2 h) = 10 mi in 2 hours. That will put it 2+10 = 12 miles from Sampson's starting location.

Samson can run 12 miles in time ...

  time = distance/speed = (12 mi)/(3 mi/h) = 4 h

Sampson will get to the tiger's location after 4 hours, just as the tiger is ending its rest period.

__

The graph shows the position of Sampson (red) and the tiger (blue) x hours after the chase starts. The distance (y miles) is measured from Sampson's starting point, assuming the tiger is running away.

b

step-by-step explanation:

your answer is the frist one

hop i