According to a study of political​ prisoners, the mean duration of imprisonment for prisoners with chronic​ post-traumatic stress disorder​ (PTSD) was months. Assuming that ​months, determine a ​% confidence interval for the mean duration of​ imprisonment, ​, of all political prisoners with chronic PTSD. Interpret your answer in words.

This question is incomplete, the complete question is;

According to a study of political​ prisoners, the mean duration of imprisonment for 33 prisoners with chronic​ post-traumatic stress disorder​ (PTSD) was 34.2 months. Assuming that σ = 40 ​months.

determine a 95​% confidence interval for the mean duration of​ imprisonment, ​μ , of all political prisoners with chronic PTSD. Interpret your answer in words.

⇒ ( 20.6, 47.8 )

Therefore, 95% confidence interval for the mean duration of imprisonment μ of all political prisoners with PTSD is between 20.6 months and 47.8 months.

Step-by-step explanation:

Given the data in the question;

sample size; n = 33

standard deviation σ = 40 months

x' = 34.2 months

Now, at 95% confidence interval;

we know that z-value of 95% confidence interval is 1.96

so we substitute into the formula below;

⇒ x' ± Z( σ/√n )

⇒ 34.2 ± 1.96( 40/√33 )

⇒ 34.2 ± 13.647

so

we have

( 34.2 - 13.647 ), ( 34.2 + 13.647 )

⇒ ( 20.6, 47.8 )

Therefore, 95% confidence interval for the mean duration of imprisonment μ of all political prisoners with PTSD is between 20.6 months and 47.8 months.

step-by-step explanation:

it's d.

step-by-step explanation:

because: -1(4x + 1y) +2 (1x-3y) distribute each number into the parenthesis.

then you would get: -4x - 1y + 2x -6y combine like terms

and get: 2x -7y

hope my answer has you if not then i'm sorry.