QUICKLY!! We know that a triangle with side lengths x^2-1,2x and x^2+1 is a right triangle. Using those side lengths, find the missing triples and x-values. Write the triples in parentheses, without spaces between the numbers, and with a comma between numbers. Write the triples in order from least to greatest.

Type the correct answer in each box.

x valuepythagorean triple

3

(8,15,17)

5

(12,35,37)

Step-by-step explanation:

The given side lengths of the right triangle are;

x² - 1, 2·x and x² + 1

A Pythagorean triple are three numbers, a, b, and c, such that, we have;

a² + b² = c²

From the given side lengths, we have;

We note that (x² + 1) > (x² - 1)

(x² + 1) > 2·x for x > 1

Therefore, with (x² + 1) as the hypotenuse side, we have;

(x² - 1)² + (2·x)² = (x² + 1)²

Therefore, when the x-value is 3, we have;

(3² - 1)² + (2 × 3)² = (3² + 1)²

8² + 6² = 10²

The least is 6² = (2 × 3)², from (2·x)²

Therefore;

The Pythagorean triple is 6, 8, 10

The order of the triple is (2·x), (x² - 1), (x² + 1)

2) The x-value for the triple, (8, 15, 17), is obtained as follows;

The least, 8 = 2·x

∴ x = 8/2 = 4

The x-value = 4

3) The Pythagorean triple where the x-value = 5 is therefore;

(2·x), (x² - 1), (x² + 1), where x = 5 gives;  (2×5 = 10), (5² - 1 = 24), (5² + 1 = 26)

Therefore, the Pythagorean triple where x = 5 is 10, 24, and 26

4) The x-value for the Pythagorean triple (12, 35, 37) is given by 12 = 2·x

Therefore, x = 12/2 = 6

Therefore, we get;

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