Mathematics, 09.07.2021 15:10 badpotterchris
Given: ∠1 = ∠2; ∠C = ∠D Prove: CX = DX | 1. ∠ ≅ ∠ 1 2; ∠ ≅ ∠ C D| 1. | 2. AB = AB | 2. | 3. ΔABC ≅ ΔBAD| 3. | 4. AD = BC | 4. | 5. AD = AX + DX | 5. | 6. BC = BX + CX | 6. | 7. AX + DX = BX + CX | 7. | 8. AX = BX | 8. | If 2 ∠'s of a Δ are =, then the sides opposite them are = 9. DX = CX | 9. | 10. CX = DX | 10.
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Given: ∠1 = ∠2; ∠C = ∠D Prove: CX = DX | 1. ∠ ≅ ∠ 1 2; ∠ ≅ ∠ C D| 1. | 2. AB = AB | 2. | 3. ΔABC...
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