A²,b²,c² are consecutive perfect squares. How many natura numbers are lying between a² and c², if a>0

The quantity of natural numbers between and is .

Step-by-step explanation:

If , and are consecutive perfect squares, then both , and are natural numbers and we have the following quantities of natural numbers:

Between and :

And the quantity of natural numbers between and is:

Between and :

And the quantity of natural numbers between and is:

And the quantity of natural numbers between and is:

Please observe that the component +1 represents the natural number

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions