The parallel chord lie on opposite sides of the center of a circle of radius 13cm. Their lengths are 10cm and 24cm respectively. What is the between the chords

We are required to find the distance between both chords.

17 cm

Step-by-step explanation:

The two chords are parallel to each other.

This means that a perpendicular line drawn from the centre of the circle will divide both of them into 2 equal sides.

This is depicted in the image attached.

From the Image,the diagonal drawn from one end of either chord through the centre will form the hypotenuse side of either chords.

Thus, using pythagoras theorem, we have for the chord that has a length of 10 cm. Perpendicular distance from centre of chord to centre of circle is;

d = √(13² - 5²)

d = √144

d = 12

Similarly, for chord with length = 24 cm, we have;

d' = √(13² - 12²)

d' = √25

d' = 5

Therefore, distance between chords = d + d' = 12 + 5 = 17 cm

f

step-by-step explanation:

f

d is the correct answer

step-by-step explanation:

x= 8 because 3x = 3 * 8, and 3*8 = 24