An employment agency specializing in temporary construction help pays heavy equipment operators $123 per day and general laborers $89 per day. If thirty-one people were hired and the payroll was $3507, how many heavy equipment operators were employed? How many laborers?
The number of heavy equipment operators hired was
The number of general laborers hired was

The number of operators is 22 and the number of laborers is 9

Step-by-step explanation:

This is a 2 line equation system

I'll call the laborers "L" and the equipment operators "E"

The first line of the system is pretty much telling me that the number of laborers plus the number of operators is 31:

L + E = 31

Now we need to calculate the money:

Since we know that laborers are paid $89 per day we're gonna multiply them by that. Same thing with the operator, but the value is now $123

89L + 123E = 3507

Our two line system is like this:

L + E = 31

89L + 123E = 3507

We need either L or E to be the same in both of the equations so that when I subtract one from another I can find the value of one of the variables

I'll choose L cause it's the lower number, so I'll multiply the upper equation:

L+E=31 === *89 > 89L + 89E = 2.759

Now we have these equations:

89L + 89E = 2.759

89L + 123E = 3507

Now I'm gonna subtract the lower equation from the upper one:

89L - 89L + 123E - 89E = 3507 - 2759

Since L is now zero it disappears, and by making the other calculations we have:

34E = 748

E = 22

Since E = 22, we can use the value in our first equation:

E+L=31 ===> 22+L=31 ===> L=9

Got it! The number of operators is 22 and the number of laborers is 9.

If you wanna double check this you can calculate the amount of money they're paid, which should add up to $3507:

22 operators * $123 = $2706

9 laborers * $89 = $801

2706+801 = $3507

We're good

If this helped you at all, would it be too much asking for brainliest?

I would really appreciate it

Have a great one

options a,b,c are the right answer.

step-by-step explanation:

a linear parent function is always represented as y = x

if we write this function in the form of y=mx+c

⇒

or  

now if we plot a graph we will find these characteristics:

1) y intercept of the graph is zero so its a straight line passing through origin.

2) as we can see in both the forms of function written, values of x and y may be either positive or negative for the positive slope means points on the graph are either in first quadrant or in third one.

3) it's slope is one.

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)