I need help on this graphing question if anyone can, please help me

Answer/Step-by-step explanation:

Given:

f(x) = 2x + 2

Domain = {-5, -1, 2, 3}

To write the range of f using set notation, substitute each domain value into f(x) = 2x + 2 to get each corresponding range value that will make up the set.

Thus:

✔️f(-5) = 2(-5) + 2

= -10 + 2

f(-5) = -8

✔️f(-1) = 2(-1) + 2

= -2 + 2

f(-1) = 0

✔️f(2) = 2(2) + 2

= 4 + 2

f(-1) = 6

✔️f(3) = 2(3) + 2

= 6 + 2

f(3) = 8

Range of f using set notation = {-8, 0, 6, 8}

✔️Graph f by plotting the domain values on the x-axis against the corresponding range values on the y-axis as shown in the attachment below:

*See attachment for the graph of f

is there a picture

step-by-step explanation:

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1