Let be the set of permutations of whose first term is a prime. If we choose a permutation at random from , what is the probability that the third term is equal to

Step-by-step explanation:

Given

Required

Probability the third term is 3

First, we calculate the possible set.

The first must be prime (i.e. 2, 3 and 5) --- 3 numbers

So, the number of set is:

Next, the number of sets if the third term must be 2

i.e. 1 or 5

---- i.e. remove the already selected first term and the 3rd the compulsory third term

i.e. the digit 2

So

So, the probability is:

b). 4320 have a nice day

about 168 miles

step-by-step explanation: