Find the TWO integers whos product is -12 and whose sum is 1
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Step-by-step explanation:

Given :-

The sum of two numbers is 1 .

The product of the nos . is 12 .

And we need to find out the numbers. So let us take ,

First number be x

Second number be 1-x .

According to first condition :-

Hence the numbers are 4 and -3

Step-by-step explanation:

we are given two conditions

let the two integers be x and y respectively according to the first condition

according to the second condition:

now notice that we have two variables therefore ended up with a simultaneous equation so to solve the simultaneous equation cancel x from both sides of the second equation which yields:

now substitute the got value of y to the first equation which yields:

distribute:

add 12 in both sides:

rearrange it to standard form:

divide both sides by -1:

factor:

by Zero product property we acquire:

solve the equations for x therefore,

when x is -3 then y is

simplify

when x is 4 y is

simplify:

hence,

step-by-step explanation:

a rhombus is a parallelogram enjoying his symmetry.

-22

times both sides by 2, times () by 8, add alile terms, move terms, add alike and caculate divide both sides by 3