For Event B, compute the absolute relative difference |5000−()|()
|
f
5000
−
P
(
B
)
|
P
(
B
)
, where f5000 is the relative frequency of Event B on the 5,000th trial and P(B) is the classical probability of Event B. Round your answer to three decimal places.

his chances of getting a coin of higher value is 4/19

step-by-step explanation:

hello :

by applying the distributive property :

6 × 4.3 = 6 × ( 4 + 0.3 )

            =   (6 ×   4) + (6 ×   0.3)

            = 24 + 1.8

6 × 4.3 = 25.8

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