The following data were obtained for the growth of a sheep population introduced into a new environment on the island of Tasmania.
t (year) 1814 1824 1834 1844 1854 1864
P(t) 125 275 830 1200 1750 1650
Find the natural cubic splines that pass through these data points by doing the following:
(a) Translate the time coordinate to start from ť = 0
(b) Derive an appropriate system of spline equations

the 1st digit is in the 100s n its 1

step-by-step explanation:

3,589÷18 = 199.389

so the first digit of the quotient is in the 100s n its 1

thats one

step-by-step explanation:

no oblique asymptote

step-by-step explanation:

to find the oblique asymptote of f(x)

here numerator has degree 1 and denomintor degree 2

degree of numerator < degree of denominator

hence there is no oblique asymptote

when the degree of the denominator > that of the numerator, we saw that the value in the denominator got so much bigger, so quickly,   giving us a horizontal asymptote of the x-axis. or we can write

f(x) = a polynomial of x + a proper fraction.

in this case only we have oblique asymptotes but not when numerator has less degree.