Please help me, i suck at this​

(5, -5)

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Equality Properties

Algebra I

Step-by-step explanation:

Step 1: Define Systems

2x - 3y = 25

5x + 3y = 10

Step 2: Solve for x

Elimination

Step 3: Solve for y

(5,-5)

Step-by-step explanation:

Hi there!

We are given this system of equations:

2x-3y=25

5x+3y=10

and the question asks to solve it by elimination

To solve by elimination, we will add the equations together to clear one variable, solve for the variable that wasn't cleared, then use the value of the variable that wasn't cleared to solve for the variable that was cleared earlier

Before we clear a variable, the coefficients  in front of the variable that we want to clear need to be opposites (ex. if we wanted to clear x, the coefficients of x in the systems have to be -2 and 2, as that would equal 0).

In this case, the coefficients in front of y in the equations are -3 and 3 respectively. That equals 0, so y would be cleared if we added the equations together

so we don't have to multiply or divide by anything prior to clearing

Let's add the equations together. Remember that y will be cleared, as (-3y+3y=0)

2x-3y=25

+

5x+3y=10

7x+0=35

subtract 0 from both sides

7x=35

divide both sides by 7

x=5

we found the value of x

now we need to find the value of y

substitute 5 as x into either one of the equations to solve for y

if we were to do it into 2x-3y=25 for instance,

2(5)-3y=25

multiply

10-3y=25

subtract 10 from both sides

-3y=15

divide both sides by -3

y=-5

So the answer is x=5, y=-5, or as point (5,-5)

Hope this helps! :)

yes

step-by-step explanation:

so of course you want to start by plugging the 5 in which goes to 7(5)+3(5)=50 because 7*5=35 and 3*5=15 and then add them together, then plug in the 5 to the other equation as well 9(5)+5=50 because 9*5= 45 and then add 5 and so yes they are equivalent.