50 points and brainless 1. In a board game, you must roll two 6-sided number cubes. You can only start the game if you roll a 3 on at least one of the number cubes.
(a) Make a list of all the different possible outcomes when two number cubes are rolled.

(b) What fraction of the possible outcomes is favorable?

(c) Suppose you rolled the two number cubes 100 times, would you expect at least one 3 more or less than 34 times? Explain.

The answer for (a) is

1, 1     2, 2    3, 3    4, 4    5, 5    6, 6

1, 2    2, 3    3, 4    4, 5    5, 6

1, 3    2, 4    3, 5    4, 6

1, 4    2, 5    3, 6

1, 5    2, 6

1, 6    

The answer for (b) is 6/21 or 0.285714286

The answer for (c) is Less than. {its in the explanation}

Explanation:

(a)- Its not really hard, it just takes a bit of time.

(b)- The total number of possibilities is 21. Favorable outcomes would have a 3 as one of the dice, and only 6 of the 21 outcomes has a 3. (they are in bold)

There are only 21 possible outcomes because the prompt says "Make a list of all the different possible outcomes." For example: I have 3, 4 as an outcome, but not 4, 3 because that would be the same outcome.

(c)- Less than, because the possibility of getting an outcome with at least one 3 is only 0.285714286. If you multiply that by 100, thats only 28.5714286, or 29, still less than 34.

none of the option is correct.

step-by-step explanation:

it says to find which expression equals 9^3 sqrt 10 = ?

9^3 sqrt 10 = 729 sqrt 10.

checking option a. 5 sqrt 10 + 4 sqrt 10

5 sqrt 10 + 4 sqrt 10

= 9 sqrt 10.

checking option b. 5^3 sqrt 10 + 4^3 sqrt 10

5^3 sqrt 10 + 4^3 sqrt 10

= 125 sqrt 10 + 64 sqrt 10

= 189 sqrt 10.

checking option c. 5 sqrt 10 + 4^3 sqrt 10

5 sqrt 10 + 4^3 sqrt 10

= 5 sqrt 10 + 64 sqrt 10

= 69 sqrt 10.

checking option d. 5^3 sqrt 10 + 4 sqrt 10

5^3 sqrt 10 + 4 sqrt 10

= 125 sqrt 10 + 4 sqrt 10

= 129 sqrt 10.

hence, none of the option is correct.