Graph the function y = f(x) = x2. If the graph of the given function were shifted six units to the left, the new graph would represent the function,
A.) y=f(x+6) =(x+6)^2
B.) y=f(x-6)=(x-6)^2
C.) y=f(x)+6=x^2+6
D.) y=f(x)-6=x^2-6
If the graph of the given function were shifted upward by six units, the new graph would represent the function,
A.) y=f(x+6)=(x+6)^2
B.) y=f(x-6)=(x-6)^2
C.) y=f(x)+6=x^2+6
D.) y=f(x)-6=x^2-6
For the same y-values, the corresponding x-values of the function,
A.) y=f(3x/2)=(3x/2)^2
B.) y=f(2x/3)=(2x/3)^2
C.) y=f(x+1.5)=(x+1.5)^2
D.) y=f(x)+1.5=x^2+1.5
are 1.5 times of the x-values of the function y = f(x) = x2.

first, you divide the triangle in two, tô form a retangle triangle. after, using pythagoream theorem:

18^2 = 14^2 + (x/2)^2

(x^2/4) + 196 = 324

x^2/4 = 324 - 196

x^2/4 = 128

x^2 = 512

x = √512

x = √2^9

x = 16√2 cm

i hope i you.

249824

hope this !

secant-secant formula:

(whole secant) x (external part) =           (whole secant) x (external part)

(8+y-2) *8=                                           (y+4+6) *6

(y+6)*8 = (y+10) *6

distribute

8y+48 = 6y +60

subtract 6y from each side

2y +48 = 60

subtract 48 from each side

2y = 12

divide by 2

y = 6

sv =     (y+4+6)

sv   = 6+4+6

sv = 16

43

step-by-step explanation:

not sure if this is supposed to be a trick question. 43 is the only one that makes any sense.