Jamal opens a savings account with a starting balance of $200 and plans to deposit $75 each week after opening the account. His savings over time is
represented by the graph below. How would this graph change if Jamal
decided to deposit $100 each week instead?
y 75x200
316.350)
У
650+
625
600
575
350
525
500
475
450
15.575)
14,500)
13.425)
400
375
350
12.350)
325
300
(87275)
250
225
2000, 200)
1 2 3 4 5 6 7 8 10 11 12
x = Number of weeks
y = Dollars in account

A. The new graph would have the same steepness as the original graph and the y-intercept would shift up

B. The new graph would be steeper than the original graph and the y-intercept would remain the same

C. The new graph would be less steep than the original graph and the y-intercept would remain the same

D. The new graph would have the same steepness as the original graph and the y-intercept would shift down

n

step-by-step explanation:

you need to give us more information since we can't answer

irst, find the z score of a score of 80. this is given by the formula z = (x-u)/o, where x is the score, u is the mean, and o is the standard deviation. this gives

z = (80-78)/12 = 1/6 = .1667

now, find what percentile a z score of 1/6 correlates to in the normal distribution.

a z score of 1/6 = .1667 is equivalent to the 56.36th percentile of the distribution. so the probability a score is over this is 1-.5636 = .4364

the mean of a sample mean is equal to the original mean. however, the standard deviation of a sample mean is equal to the original standard deviation divided by the square root of n (sample size). so the new standard deviation is 12/sqrt(16) = 3.

the new z score is 80-78/3 = 2/3 = .667. this is equivalent to the 74.86th percentile. so the probability that the mean will be greater than this score is 1-.7486 = .2514.