The formula for velocity of an object is the equals d over t where he is a velocity of the object t is the distance traveled and t is a time in class well that distance is terrible if you had only this formula to work with what would your first step be to determine how long it takes for the light to return fitness center one additional information do you need to calculate this and solve the variable you're looking for

Step-by-step explanation:

The question is mixed up with details of another question. See comment for original question

Given

Solving (a): Solve for time

We have:

Cross multiply

Make t the subject

Solving (b): Solve for distance

We have:

Cross multiply

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine

-362

step-by-step explanation:

(12)(4)+2(12)-34(12)+2(12)-3

  \/         \/         \/         \/

  48 +   24 -   408 + 24 - 3

      \   /               \   /

          72     -     432 - 3 = -363