Chapter Constructions
Example 21.14
Using a ruler and
a) Construct
| AB1 = 6
ZBAC
- Const
Xoom
6 cm
m not drawn to scale
lution
Fig 21.35
Exxl
The side of a tricingle ore in the said
bisilo. If the perimeter of the traengle
288cm find the whole
a shortest side
3
and a pair of compasses only:
ct a triangle ABC such that
=10.4 cm, ZBAC = 90° and
BC=30°
using (i) above and any additional
nes, determine a point P on BC which is
equidistant from A and B.
olution
i) Refer to Fig 21.36. Note that
means angle BAC with the angle at
ii) The point is equidistant from
Therefore the locus of the po
bisector ofline AB but the point
be on BC. Therefore Pis
of line BC ar​

(23*2)-12=x     x=34

step-by-step explanation:

answer: on graphs, the open and closed circles, or vertical asymptotes drawn as dashed lines us identify discontinuities.

as before, graphs and tables allow us to estimate at best.

when working with formulas, getting zero in the denominator indicates a point of discontinuity.

when working with piecewise-defined functions, check for discontinuities at the transition points where one piece ends and the next begins.

step-by-step explanation:

answerim :

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step-by-step explanation:

im not sure but my dad knows

area of rectangle a is 2 times that of rectangle b that means 2x+x =   36cm^2

3x = 36cm ^2

x = 36/3

x= 12cm^2

and 2x = 24cm^2

now side of square = are divided by sides = 36/4 = 6cm

that means length of rectangle a and b is 6cm too

now for rectangle a,

l*b = area

= 6*y=24

y=24/6 = 4

therefore dimensions of rectangle a are- length = 6cm, breadth = 4cm

and for rectangle b, length = 6cm and breadth = 6-4 = 2cm.

hope this .