Eight less than four times a number is less than 56. What are the possible values of that number? X> 12
x < 12
ООО
x < 16
O x> 16

x < 16

Step-by-step explanation:

Let the number be x

Four time the number = 4x

Eight less than four times the number = 4x - 8

Eight less than four times the number is less than 56,

          that is , 4x - 8  < 56

                      4x - 8 + 8 < 56 + 8                    [ adding both sides by 8 ]

                        4x + 0 < 64

                              4x < 64                             [ divide both sides by 4 ]

                                 x < 16

(b) 240

step-by-step explanation:

first, we use the pythagorean formula using the given side lengths to find x. then we use x to find the side lengths. then we add the side lengths to find the perimeter.

pythagorean theorem formula:

a^2 + b^2 = c^2

(x - 20)^2 + (x - 40)^2 = x^2

x^2 - 40x + 400 + x^2 - 80x + 1600 = x^2

x^2 -120x + 2000 = 0

(x - 100)(x - 20) = 0

x - 100 = 0 or x - 20 = 0

x = 100 or x = 20

we see that the solution x = 20 must be discarded because it will give a negative side length and a side length of 0. the only valid solution is x = 100.

perimeter = sum of the lengths of the sides

perimeter = x + x - 20 + x - 40

perimeter = 3x - 60

replace x with 100.

perimeter = 3(100) - 60

perimeter = 300 - 60

perimeter = 240

69.64%

step-by-step explanation: