Rewrite |3x+5|<or equals to 1 without absolute
value sign​

remember how the absolute value works:

|x| = x   if x ≥ 0

|x| = -x  if x < 0

Then we can rewrite:

|x| ≤ a

as:

-a ≤ x ≤ a

Now let's apply this to our case:

|3x + 5| ≤ 1

we can rewrite this as:

-1 ≤ 3x + 5 ≤ 1

We could solve this for x now, first subtracting 5 in the 3 sides:

-1 - 5 ≤ 3x + 5 - 5 ≤ 1 - 5

-6 ≤ 3x ≤ -4

now dividing by 3 in the 3 sides:

-6/3 ≤ 3x/3 ≤ -4/3

-2 ≤ x ≤ -(4/3)

So we rewrote the inequality without the absolute value part.

step-by-step explanation:

first, eliminate the parenthesis:

3

x

+

2

−

4

x

second, group like terms:

3

x

−

4

x

+

2

third, combine like terms:

(

3

−

4

)

x

+

2

→

−

1

x

+

2

→

−

x

+

2

16.9 times 2.85

step-by-step explanation: