A 3 by 3cm grid shows nine 1 by 1 cm squares and uses 24cm of wire. What length would the wire be for a similar 20 by 20cm sqaure

840 cm

Step-by-step explanation:

Given that in the question we have, : 9, 1 cm × 1 cm squares setting a 3 × 3 grid.

Therefore wire required in 3 x 3 grid is

3(3+1) + 3(3+1)

= 3 × 4 + 3 × 4

= 24 I'm

Similarly, the length of the wire required in 20 by 20 grid will be

=> 20(20+1) + 20(20+1)

=> 20 × 21 + 20 × 21

=> 420 + 420

= 840cm

x = central angle apc = measure of minor arc ac

the two angles x and 30 add to 180, so x+30 = 180 and x = 180-30 = 150. the measure of minor arc ac is 150 degrees.

what we need to do from here is find the circumference and then multiply it by x/360 since there are 360 degrees in a circle. in this case, x = 150, so x/360 = 150/360 = 15/36 = 5/12. the shortest distance along the curve from a to c is 5/12 of the distance around the entire circle (aka circumference)

c = circumference

c = pi*d

c = pi*24

c = 24pi

now multiply this by 5/12 to get

distance along minor arc ac = (5/12)*(circumference)

distance along minor arc ac = (5/12)*(24pi)

distance along minor arc ac = 10pi

the formula you can use is

l = (x/360)*pi*d

with

l = length of minor arc

x = central angle

d = diameter

which essentially is the steps we took though a bit differently.