Can someone help me with a few questions? PLEASE.

.75

p(1)= 47/274= .172

p(2)= 45/274= .164

p(3)= 43/274= .157

p(4)= 45/274= .164

p(5)= 48/274= .175

p(6)= 46/274= .168

.1

Step-by-step explanation:

Not too sure about the first one

Let's start by finding the total area of the cricle

4²π=16π

Then let's find the area of the inside

2²π=4π

subtract these to get the area of the red area

16π-4π=12π

then divide this by the whole circle

12π/16π= .75

2. sum the occurrences:

47+45+43+45+48+46= 274

Then (i think) it's just a matter of division

p(1)= 47/274= .172

p(2)= 45/274= .164

p(3)= 43/274= .157

p(4)= 45/274= .164

p(5)= 48/274= .175

p(6)= 46/274= .168

If two events are independent you can mulitply them to find their intersection

(1/6)*(3/5)= .1

Question 11.2.25

The outer circle has a diameter of 8 feet, which cuts in half to a 4 foot radius.

The area of the outer circle is A = pi*r^2 = pi*4^2 = 16pi

The inner circle has a radius of 2 feet (which is half of the diameter 4 ft), so that would lead to an area of 4pi

The difference in areas is 16pi-4pi = 12pi

The value 12pi is the area of the red ring. Divide this over 16pi to get the probability of landing in the red area

(12pi)/(16pi) = 12/16 = 3/4 = 0.75

Question 11.2.9

Add up everything in the bottom row to get 274

Then divide each value over 274 to get the corresponding probability.

For example, 47/274 = 0.172 represents the approximate probability of rolling a 1 and 45/274 = 0.164 is the approximate probability of rolling a 2 and so on.

You should have these six answers:

Those six values are approximate.

Question 11.3.13

Since A and B are independent, we can say,

P(A and B) = P(A)*P(B)

P(A and B) = (1/6)*(3/5)

P(A and B) = (1*3)/(6*5)

P(A and B) = 3/30

P(A and B) = 1/10

P(A and B) = 0.1

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it