A man has twin sons of equal height. The combined height of the man and one son is 180cm. The
combined height of the man and both sons is
252cm. Twice the man's height added to the height
of one son would be

2x - 20 = 32 20 - 3x = 8 6x - 8 = 16 -13 - 3x = -10

Refer to the table below if needed. second quadrant third quadrant fourth quadrant sin(1800- - cos(180° -) tan(180°-e) =- tane cot(1800-0) 10 it to solo 888 sin(180° +c) = - sine cos(180° +) =- cose tan(180° +c) = tane cot(180° +o) = cote sec(180° + c) = - seco csc(180° +2) = - csce sin(360° -) =- sine cos(360° -) = cose tan(360° - e) =- tane cot(360° -) = -cote sec(360° -) = seco csc(360° -) = csco sec(180° -) = csc(180° -) = csca 1991 given that sine = 3/5 and lies in quadrant ii, find the following value. tane

What is the range? can’t seem to find it out