Find the solution of the differential equation that satisfies the given initial condition. dy/dx = x/y, y(0) = −3

y=-sqrt(x^2+9)

Step-by-step explanation:

This problem can be solved with the help of separating the variables.

dy/dx=x/y

Multiply both sides by y

y dy/dx=x

Multiply both sides by dx

y dy=x dx

Integrate

y^2/2=x^2/2+c

Let's find c using the condition y(0)=-3.

(-3)^2/2=(0)^2/2+c

9/2=0+c

9/2=c.

The equation is y^2/2=x^2/2+9/2.

Let's make this a bit prettier multiplying both sides by 2:

y^2=x^2+9

Taking square root of both sides gives:

y=+/- sqrt(x^2+9)

Since we want y(0)=-3, then we will choose

y=-sqrt(x^2+9).

distance covered by pamela in 9 l of fuel = 99km

let us apply unitary method here.

distance covered by pamela in 1 l of fuel =99/9 =11 km

now let us find distance covered by pamela if she has 12 l of fuel.

distance covered in 12 l = distance covered in 1 l of fuel * 12

we know that distance covered by here in 1 l is 11 km.

so distance covered in 12 l of fuel = 11*12 = 132 km.