X, Y and Z are three points on a map. Y is 85km and on a bearing of 190° from X. Z is on a bearing of 140°, from Y. Z is due south of X. Calculate the distance between X and Z rounded to 1 DP

The distance between X and Z is approximately 95.99 km

Step-by-step explanation:

(For Diagram Please Find in Attachment)

The distance of Y from X = 85 km

The bearing of Y from X = 190°

The bearing of Z from Y = 140°  

The bearing of Z from X = 180°

Now,  

∠YZX = 180° - (130° + 10°) = 40°

(85 km)/sin(40°) = XZ/(sin(130°))

XZ = sin(130°) × (85 km)/sin(30°) ≈ 95.99 km

The distance between X and Z ≈ 95.99 km

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.

i think its a and d

step-by-step explanation: