Mr. Alhammadi is shopping for school supplies with his children. Rashed selected 3 one-inch binders and 2 two-inch binders, which cost a total of 29 dirhams. Matar selected 5 one-inch binders and 2 two-inch binders, which cost a total of 35 dirhams. Write a system of equations that represents the above situation.

I need help ASAP please :(

3x + 2y = 29

5x + 2y = 35

Step-by-step explanation:

Let

x = cost of one-inch binders

y = cost of two-inch binders

Rasheed:

3x + 2y = 29 (1)

Matar:

5x + 2y = 35 (2)

3x + 2y = 29 (1)

5x + 2y = 35 (2)

Using elimination method, subtract (1) from (2)

5x - 3x = 35 - 29

2x = 6

x = 6/2

x = 3

Substitute x = 3 into (1)

3x + 2y = 29 (1)

3(3) + 2y = 29

9 + 2y = 29

2y = 29 - 9

2y = 20

y = 20/2

y = 10

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°

the answer is b.

64

step-by-step explanation:

c=2πr=2·π·8≈64