An indoor track is made up of a rectangular region with two semi-circles at the ends. The distance around the track is 400 meters. Determine the radius of the semicircular ends of the track in terms of y.

r = (200 - y)/π

Step-by-step explanation:

The question details  includes;

The shape of the indoor track = Two semi-circular ends and a mid rectangular region

The distance around the indoor track = 400 meters

The radius, r, of the semicircular ends in terms of y = Required

Let y represent the length of the rectangular middle area of the track, we have;

The perimeter of the indoor track = The distance around the track = 400 m

The perimeter of the indoor track = 2 × π·r + 2 × y = 400

2 × (π·r + y) = 400

∴ π·r + y = 400/2 = 200

r = (200 - y)/π

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step-by-step explanation:

answer:

total cost for tiles and paints is $924.  

step-by-step explanation:

we have been given that a community hall is in the shape of a cuboid. the hall is 40m long 15m high and 3m wide.

the paint will be required for 4 walls and ceiling.

let us find area of walls and ceiling.

therefore, the area of walls and ceiling is 1410 square meters.

given: cost for 10 litre of paint is $10 and 10 litre paint covers 25 square meter. therefore,

therefore, the total painting cost is $564.

tiles will be required for floor. let us find the area of floor.

given: 1m squared floor tiles costs $3. so,

therefore, the total tiles cost is $360.

now let us find combined total cost of tiles and paint.

therefore, the combined total cost of tiles and paint is $924.