Pls help this question bamboozles me and I am now sitting here confused

10+3pi

Step-by-step explanation:

The perimeter of of the shaded region is

AC+CT+marcSBT+SA

*Finding AC

The diagonals of a rectangle are equal is measurement. Since RB is a radius of the circle, then RB is 6. Since AC and RB are both diagonals of the rectangle, then AC is also 6.

*Finding CT

CT=RT-RC where RC is the width of the rectangle

Also RT is a radius so we have that

CT=6-RC

*Finding marcSBT

The circumference of a whole circle is 2pi*r.

We have a quarter of this with r=6.

1/4*2pi(6)

1/4*12pi

3pi

*Finding SA

SA=RS-AR

RS is a radius of the circle and AR is the length of the rectangle.

So we have that this can be rewritten as

SA=6-AR

Let's put these parts together:

6+6-RC+3pi+6-AR

Simplifying:

18-RC-AR+3pi

18-(RC+AR)+3pi

18-8+3pi (Remember length plus width equal 8)

10+3pi

location: point 0

step-by-step explanation:

well, -8 to 10 on a number line is 18 spaces.

1/9 of 18 is 2.

so, 4/9 of 18 must be 8.

8 spaces from -8 (a) is 0.

so, 4/9 of the way from -8 to 10 is 0!

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )