Which transformation performed on Triangle PQR will create an image Triangle P'Q'R' contained entirely in Quadrant II? A
a counter-clockwise rotation of 90 degrees about the origin

B
a reflection over the x-axis

C
a reflection over the y-axis

D
a translation of 2 units to the left

john got lost so he didn't know what to do and it was crazy because he didn't except it

step-by-step explanation:

123123 step byt step

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)