What is the vertex of x^2

The vertex is (0,0)

Step-by-step explanation:

To find the x coordinate of the vertex

x = -b/2a  where ax^2 +bx +c

a=1 b=0 c=0

x = -0/2(1) = 0

The y value is found by substituting into the equation

y = (0)^2 =0

The vertex is (0,0)

a. -0.3 > -0.33

the required function is .

step-by-step explanation:

from the given table it is noticed that the graph passing through (-3,7), (0,4), (3,1) and (8,-4).

it is a linear function because the value of y is decrease by one as the value of x increase by 1.

the slope of the function is

the slope of the function is -1 and the y-intercept is 4.

the slope intercept form is

where, m is slope and b is y-intercept.

therefore the required function is . the graph of this function is shown below.