Find the equation of the line with a slope of 2 and a point of (5,11) PLEASE HELP

y=2x+1

Step-by-step explanation:

Hi there!

We are given the slope (m), which is 2, as well as the point (5,11).

We need to find the equation of the line.

There are 3 ways to write the equation of the line, but the most common type is slope-intercept form, or y=mx+b, where m is the slope and b is the y intercept

We're already given the slope (2), so we can substitute it into the equation right away

here's the equation so far:

y=2x+b

now we need to find b.

We can do this by plugging (5,11) into the equation, as the line passes through that point.

Substitute x as 5 and 11 as y

11=2(5)+b

multiply

11=10+b

subtract 10 from both sides

1=b

substitute 1 as b into the equation

y=2x+1

Hope this helps! :)

the mistake in the pattern is that :

b. the decimal point was moved one too many place values each time

the correct pattern could be made by :

b. moving the decimal point to the right the same numbers of place values as the exponents