In the radius of a circle with an area of 10 inches squared is reduced by half what is the area of the new circle

Hence when the radius is halved the area is divided by 4

2.5 inches^2

Step-by-step explanation:

Given data

Area= 10inches^2

We know that the expression for the area of  a circle is given as

Area= πr^2

10= 3.142*r^2

10/3.142= r^2

r^2= 3.18

Square both sides

r= √3.18

r= 1.78 inches

Now let us half the radius and find the area of the new circle

r/2= 1.78/2

r= 0.89

Area of the new circle is

Area= 3.142*0.89^2

Area= 3.142*0.7921

Area= 2.5 inches^2

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2